Question
Let X = {2, 4, 6, … ,20} be the Universe of discourse,
`\A^\~ 1 = {\left( 2,0.5 \right),\left( 4,0.9 \right),\left( 6,0.2 \right),\left( 8,0.4 \right),\left( 10,0.5 \right),\left( 12,0.2 \right),\left( 14,0.4} \right),\left( {16,0.0} \right),\left( 18,0.5 \right),\left( 20,0.8 \right)} `
And
`\B^{ \~ 1} = \{ \left( 2,0.5 \right),\left( 4,0.5 \right),\left( 6,0.5 \right),\left( 8,0.2 \right),\left( 10,0.3} \right),\left(12,0.3 \right),\left( 14,0.5 \right),\left( 16,0.8 \right),\left( 18,0.2\right),\left(20,0.4 \right)}`
Be two fuzzy sets on X. Determine `\A^{ \~ 1} \cup B^{ \~ 1}`
Solutions:
Here
X = {2, 4, 6, … ,20} be the Universe of discourse.
First, we find `\A^{ \~1}` and `\B^{ \~1}`
We know that
`\A^{ \~1} = 1 - \mu A^{ \~ 1}`
So,
`\A^{ \~1} = {\left( 2,0.5 \right),\left( 4,0.1 \right),\left( 6,0. \right),\left( 8,0.6 \right),\left( 10,0.5 \right),\left( 12,0.8 \right),\left( 14,0.6 \right),\left( 16,1.0 \right),\left( 18,0.5 \right),\left( 20,0.2 \right)}`
And
`\B^{ \~1} = { \left( 2,0.5 \right),\left( 4,0.5 \right),\left( 6,0.5 \right),\left( 8,0.8 \right),\left( 10,0.7 \right),\left( 12,0.7 \right),\left( 14,0.5 \right),\left( 16,0.2 \right),\left( 18,0.8 \right),\left( 20,0.6 \right)} `
Now
`\A^{ \~ 1} \cup B^{ \~ 1`} = `{\left( 2,0.5 \right),\left( 4,0.5 \right),\left( 6,0.8 \right),\left( 8,0.8 \right),\left( 10,0.7 \right),\left( 12,0.8 \right),\left( 14,0.6 \right),\left( 16,1.0 \right),\left( 18,0.8 \right),\left( 20,0.6 \right)}`